如何在不同编程语言中获取现在的Unix时间戳(Unix timestamp)？
| Java | time |
| JavaScript | Math.round(new Date().getTime()/1000) getTime()返回数值的单位是毫秒 |
| Microsoft .NET / C# | epoch = (DateTime.Now.ToUniversalTime().Ticks - 621355968000000000) / 10000000 |
| MySQL | SELECT unix_timestamp(now()) |
| Perl | time |
| PHP | time() |
| PostgreSQL | SELECT extract(epoch FROM now()) |
| Python | 先 import time 然后 time.time() |
| Ruby | 获取Unix时间戳：Time.now 或 Time.new 显示Unix时间戳：Time.now.to_i |
| SQL Server | SELECT DATEDIFF(s, '1970-01-01 00:00:00', GETUTCDATE()) |
| Unix / Linux | date +%s |
| VBScript / ASP | DateDiff("s", "01/01/1970 00:00:00", Now()) |
| 其他操作系统(如果Perl被安装在系统中) | 命令行状态：perl -e "print time" |
如何在不同编程语言中实现Unix时间戳( Unix timestamp) → 普通时间？
| Java | String date = new java.text.SimpleDateFormat("dd/MM/yyyy HH:mm:ss").format(new java.util.Date(Unix timestamp * 1000)) |
| JavaScript | 先 var unixTimestamp = new Date(Unix timestamp * 1000) 然后commonTime = unixTimestamp.toLocaleString() |
| Linux | date -d @Unix timestamp |
| MySQL | from_unixtime(Unix timestamp) |
| Perl | 先 my $time = Unix timestamp 然后 my ($sec, $min, $hour, $day, $month, $year) = (localtime($time))[0,1,2,3,4,5,6] |
| PHP | date('r', Unix timestamp) |
| PostgreSQL | SELECT TIMESTAMP WITH TIME ZONE 'epoch' + Unix timestamp) * INTERVAL '1 second'; |
| Python | 先 import time 然后 time.gmtime(Unix timestamp) |
| Ruby | Time.at(Unix timestamp) |
| SQL Server | DATEADD(s, Unix timestamp, '1970-01-01 00:00:00') |
| VBScript / ASP | DateAdd("s", Unix timestamp, "01/01/1970 00:00:00") |
| 其他操作系统(如果Perl被安装在系统中) | 命令行状态：perl -e "print scalar(localtime(Unix timestamp))" |
如何在不同编程语言中实现普通时间 → Unix时间戳( Unix timestamp)？
| Java | long epoch = new java.text.SimpleDateFormat("dd/MM/yyyy HH:mm:ss").parse("01/01/1970 01:00:00"); |
| JavaScript | var commonTime = new Date(Date.UTC(year, month - 1, day, hour,minute, second)) |
| MySQL | SELECT unix_timestamp(time) 时间格式: YYYY-MM-DD HH:MM:SS 或 YYMMDD 或 YYYYMMDD |
| Perl | 先 use Time::Local 然后 my $time = timelocal($sec, $min, $hour, $day, $month, $year); |
| PHP | mktime(hour, minute, second, day, month, year) |
| PostgreSQL | SELECT extract(epoch FROM date('YYYY-MM-DD HH:MM:SS')); |
| Python | 先 import time 然后 int(time.mktime(time.strptime('YYYY-MM-DD HH:MM:SS', '%Y-%m-%d %H:%M:%S'))) |
| Ruby | Time.local(year, month, day, hour, minute, second) |
| SQL Server | SELECT DATEDIFF(s, '1970-01-01 00:00:00', time) |
| Unix / Linux | date +%s -d"Jan 1, 1970 00:00:01" |
| VBScript / ASP | DateDiff("s", "01/01/1970 00:00:00", time) |